HDU 2612 Find a way
Description
Pass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally. Leave Ningbo one year, yifenfei have many people to meet. Especially a good friend Merceki. Yifenfei’s home is at the countryside, but Merceki’s home is in the center of city. So yifenfei made arrangements with Merceki to meet at a KFC. There are many KFC in Ningbo, they want to choose one that let the total time to it be most smallest. Now give you a Ningbo map, Both yifenfei and Merceki can move up, down ,left, right to the adjacent road by cost 11 minutes.
题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=2612
Input
The input contains multiple test cases. Each test case include, first two integers n, m. (2<=n,m<=200). Next n lines, each line included m character.
‘Y’ express yifenfei initial position.
‘M’ express Merceki initial position.
‘#’ forbid road;
‘.’ Road.
‘@’ KCF
Output
For each test case output the minimum total time that both yifenfei and Merceki to arrival one of KFC.You may sure there is always have a KFC that can let them meet.
Sample Input
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Sample Output
66
88
66
大意
Y和M两个人要在任意一个KFC见面,求两人路径和中最短的一个
思路
两次BFS求出两人到所有KFC的路径长,再找出和最短的那个
Code
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突然发现DFS比BFS更难以梳理清楚、难实现,因为涉及递归……
相较于DFS,BFS就显得友好多了……