HDU 4292 Food(最大流再优化?)
Description
与POJ 3281 Dining相似,人、食物、饮料,不同的是现在食物、饮料数目不止一份
最大流建图:
- 人 拆点(每人匹配一食物一饮料)
- 食物与人之间的容量设为1或INF都行
优化
- 字符串用
scanf("%s", str)
比循环getchar快?- main函数调用其他函数耗时?add里写两份
- BFS出口改了……
- DFS形式改了,添加了一句
deep[s] = -1;
- 犯的大错误:
Code
#include <set>
#include <map>
#include <stack>
#include <queue>
#include <ctime>
#include <cmath>
#include <cstdio>
#include <vector>
#include <bitset>
#include <string>
#include <cstring>
#include <sstream>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <functional>
#define eps 1e-8
#define PI acos(-1.0)
#define ll long long
using namespace std;
const int mod = 1e9 + 7;
const int INF = 0x3f3f3f3f;
#define Close ios::sync_with_stdio(false);
const int N = 805;
int nn, ff, dd, maxflow, deep[N];
struct edge
{
int to, w, pre;
} a[200005];
int cnt = -1;
int head[N], start, over, q[N], fro, bac;
void add(int from, int to, int w)
{
a[++cnt].to = to;
a[cnt].pre = head[from];
a[cnt].w = w;
head[from] = cnt;
a[++cnt].to = from;
a[cnt].pre = head[to];
a[cnt].w = 0;
head[to] = cnt;
}
bool bfs()
{
memset(deep, -1, sizeof(deep));
fro = bac = 0;
q[bac++] = start, deep[start] = 0;
while(fro < bac)
{
int first = q[fro++];
// if(first == over)
// return true;
for(int i = head[first]; i != -1; i = a[i].pre)
{
int v = a[i].to;
if(deep[v] < 0 && a[i].w > 0)
{
deep[v] = deep[first] + 1;
q[bac++] = v;
}
}
}
// return false;
return deep[over] > 0;
}
int DFS(int s, int cap)
{
if(s == over)
return cap;
int f;
for(int i = head[s]; i != -1; i = a[i].pre)
{
int to = a[i].to;
if(a[i].w > 0 && deep[to] == deep[s] + 1 &&
(f = DFS(to, min(cap, a[i].w))) )
{
a[i].w -= f;
a[i ^ 1].w += f;
return f;
}
}
deep[s] = -1;
return 0;
}
void Dinic()
{
int temp;
while(bfs())
while((temp = DFS(start, INF)) > 0)
maxflow += temp;
}
int main()
{
while(scanf("%d%d%d", &nn, &ff, &dd) != EOF)
{
memset(head, -1, sizeof(head));
int tem;
cnt = -1, maxflow = start = 0;
over = 1 + dd + 2 * nn + ff;
for(int i = 1; i <= ff; ++i)
{
scanf("%d", &tem);
add(start, i, tem);
}
for(int i = 1; i <= nn; ++i)
add(i + ff, i + nn + ff, 1);
for(int i = 1; i <= dd; ++i)
{
scanf("%d", &tem);
add(i + 2 * nn + ff, over, tem);
}
char str[805];
for(int i = 1; i <= nn; ++i)
{
scanf("%s", str);
for(int j = 0; j < ff; ++j)
if(str[j] == 'Y')
add(j + 1, i + ff, 1);
}
for(int i = 1; i <= nn; ++i)
{
scanf("%s", str);
for(int j = 0; j < dd; ++j)
if(str[j] == 'Y')
add(i + nn + ff, j + 1 + 2 * nn + ff, 1);
}
Dinic();
cout << maxflow << '\n';
}
return 0;
}